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41127537973 is a prime number
BaseRepresentation
bin100110010011011001…
…000110110100110101
310221011020201101211011
4212103121012310311
51133212122203343
630521013512221
72654115206344
oct462331066465
9127136641734
1041127537973
1116495472005
127b79642671
133b558556b2
141dc2237b5b
15110a9ac29d
hex993646d35

41127537973 has 2 divisors, whose sum is σ = 41127537974. Its totient is φ = 41127537972.

The previous prime is 41127537947. The next prime is 41127538007. The reversal of 41127537973 is 37973572114.

It is a happy number.

41127537973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24819481764 + 16308056209 = 157542^2 + 127703^2 .

It is a cyclic number.

It is not a de Polignac number, because 41127537973 - 233 = 32537603381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41127532973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20563768986 + 20563768987.

It is an arithmetic number, because the mean of its divisors is an integer number (20563768987).

Almost surely, 241127537973 is an apocalyptic number.

It is an amenable number.

41127537973 is a deficient number, since it is larger than the sum of its proper divisors (1).

41127537973 is an equidigital number, since it uses as much as digits as its factorization.

41127537973 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1111320, while the sum is 49.

The spelling of 41127537973 in words is "forty-one billion, one hundred twenty-seven million, five hundred thirty-seven thousand, nine hundred seventy-three".