Base | Representation |
---|---|
bin | 10010101101000011001110… |
… | …10111110110010000111011 |
3 | 12101122000121012011221121210 |
4 | 21112201213113312100323 |
5 | 20342334414312200243 |
6 | 223251003505334203 |
7 | 11443366124116053 |
oct | 1126414727662073 |
9 | 171560535157553 |
10 | 41130341131323 |
11 | 12118309337104 |
12 | 4743404037363 |
13 | 19c4761307382 |
14 | a22a0d42a563 |
15 | 4b4d6422c933 |
hex | 2568675f643b |
41130341131323 has 4 divisors (see below), whose sum is σ = 54840454841768. Its totient is φ = 27420227420880.
The previous prime is 41130341131291. The next prime is 41130341131367. The reversal of 41130341131323 is 32313114303114.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 41130341131323 - 25 = 41130341131291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41130341136323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6855056855218 + ... + 6855056855223.
It is an arithmetic number, because the mean of its divisors is an integer number (13710113710442).
Almost surely, 241130341131323 is an apocalyptic number.
41130341131323 is a deficient number, since it is larger than the sum of its proper divisors (13710113710445).
41130341131323 is a wasteful number, since it uses less digits than its factorization.
41130341131323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13710113710444.
The product of its (nonzero) digits is 7776, while the sum is 30.
Adding to 41130341131323 its reverse (32313114303114), we get a palindrome (73443455434437).
The spelling of 41130341131323 in words is "forty-one trillion, one hundred thirty billion, three hundred forty-one million, one hundred thirty-one thousand, three hundred twenty-three".
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