411310400051 has 4 divisors (see below), whose sum is σ = 424578477504. Its totient is φ = 398042322600.

The previous prime is 411310400027. The next prime is 411310400093. The reversal of 411310400051 is 150004013114.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150004013114 = 2 ⋅75002006557.

It is a cyclic number.

It is not a de Polignac number, because 411310400051 - 2²⁶ = 411243291187 is a prime.

It is a super-2 number, since 2×411310400051² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411310399996 and 411310400032.

It is not an unprimeable number, because it can be changed into a prime (411310400251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6634038680 + ... + 6634038741.

It is an arithmetic number, because the mean of its divisors is an integer number (106144619376).

Almost surely, 2^411310400051 is an apocalyptic number.

411310400051 is a deficient number, since it is larger than the sum of its proper divisors (13268077453).

411310400051 is a wasteful number, since it uses less digits than its factorization.

411310400051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13268077452.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 411310400051 its reverse (150004013114), we get a palindrome (561314413165).

The spelling of 411310400051 in words is "four hundred eleven billion, three hundred ten million, four hundred thousand, fifty-one".