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41131042333 is a prime number
BaseRepresentation
bin100110010011100110…
…011110011000011101
310221011111022102220021
4212103212132120131
51133214021323313
630521220552141
72654160043213
oct462346363035
9127144272807
1041131042333
1116497445977
127b7a852651
133b564b1794
141dc28aacb3
15110ae5078d
hex99399e61d

41131042333 has 2 divisors, whose sum is σ = 41131042334. Its totient is φ = 41131042332.

The previous prime is 41131042331. The next prime is 41131042373. The reversal of 41131042333 is 33324013114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32762086009 + 8368956324 = 181003^2 + 91482^2 .

It is a cyclic number.

It is not a de Polignac number, because 41131042333 - 21 = 41131042331 is a prime.

Together with 41131042331, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 41131042298 and 41131042307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41131042331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565521166 + 20565521167.

It is an arithmetic number, because the mean of its divisors is an integer number (20565521167).

Almost surely, 241131042333 is an apocalyptic number.

It is an amenable number.

41131042333 is a deficient number, since it is larger than the sum of its proper divisors (1).

41131042333 is an equidigital number, since it uses as much as digits as its factorization.

41131042333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 41131042333 its reverse (33324013114), we get a palindrome (74455055447).

The spelling of 41131042333 in words is "forty-one billion, one hundred thirty-one million, forty-two thousand, three hundred thirty-three".