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41132230131300 = 2235271117659158941
BaseRepresentation
bin10010101101000110101111…
…11101110011111001100100
312101122012110211200002102220
421112203113331303321210
520342402301403200200
6223251515145232340
711443464002262450
oct1126432775637144
9171565424602386
1041132230131300
1112119098659810
1247438507926b0
1319c49a2789139
14a22b4c26d660
154b4e24eb64a0
hex2568d7f73e64

41132230131300 has 576 divisors, whose sum is σ = 157342509434880. Its totient is φ = 8031937536000.

The previous prime is 41132230131299. The next prime is 41132230131397. The reversal of 41132230131300 is 313103223114.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 258709830 + ... + 258868770.

It is an arithmetic number, because the mean of its divisors is an integer number (273164078880).

Almost surely, 241132230131300 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 41132230131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (78671254717440).

41132230131300 is an abundant number, since it is smaller than the sum of its proper divisors (116210279303580).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

41132230131300 is a wasteful number, since it uses less digits than its factorization.

41132230131300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159652 (or 159645 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 41132230131300 its reverse (313103223114), we get a palindrome (41445333354414).

The spelling of 41132230131300 in words is "forty-one trillion, one hundred thirty-two billion, two hundred thirty million, one hundred thirty-one thousand, three hundred".