4113240014111 has 2 divisors, whose sum is σ = 4113240014112. Its totient is φ = 4113240014110.

The previous prime is 4113240014083. The next prime is 4113240014123. The reversal of 4113240014111 is 1114100423114.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4113240014111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4113240014161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056620007055 + 2056620007056.

It is an arithmetic number, because the mean of its divisors is an integer number (2056620007056).

Almost surely, 2^{4113240014111} is an apocalyptic number.

4113240014111 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113240014111 is an equidigital number, since it uses as much as digits as its factorization.

4113240014111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 4113240014111 its reverse (1114100423114), we get a palindrome (5227340437225).

The spelling of 4113240014111 in words is "four trillion, one hundred thirteen billion, two hundred forty million, fourteen thousand, one hundred eleven".