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411324104434127 is a prime number
BaseRepresentation
bin101110110000110001101101…
…1001000011110000111001111
31222221101012102001120221120212
41131201203123020132013033
5412403113231213343002
64014451403541233035
7152432120516302433
oct13541433310360717
91887335361527525
10411324104434127
1110a073633834a45
123a17144a40277b
1314868909603881
14738029b3849c3
15328473d216352
hex17618db21e1cf

411324104434127 has 2 divisors, whose sum is σ = 411324104434128. Its totient is φ = 411324104434126.

The previous prime is 411324104434091. The next prime is 411324104434157. The reversal of 411324104434127 is 721434401423114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 411324104434127 - 222 = 411324100239823 is a prime.

It is a super-2 number, since 2×4113241044341272 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411324104434157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205662052217063 + 205662052217064.

It is an arithmetic number, because the mean of its divisors is an integer number (205662052217064).

Almost surely, 2411324104434127 is an apocalyptic number.

411324104434127 is a deficient number, since it is larger than the sum of its proper divisors (1).

411324104434127 is an equidigital number, since it uses as much as digits as its factorization.

411324104434127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 258048, while the sum is 41.

The spelling of 411324104434127 in words is "four hundred eleven trillion, three hundred twenty-four billion, one hundred four million, four hundred thirty-four thousand, one hundred twenty-seven".