Base | Representation |
---|---|
bin | 101110110000110001101101… |
… | …1001000011110000111001111 |
3 | 1222221101012102001120221120212 |
4 | 1131201203123020132013033 |
5 | 412403113231213343002 |
6 | 4014451403541233035 |
7 | 152432120516302433 |
oct | 13541433310360717 |
9 | 1887335361527525 |
10 | 411324104434127 |
11 | 10a073633834a45 |
12 | 3a17144a40277b |
13 | 14868909603881 |
14 | 738029b3849c3 |
15 | 328473d216352 |
hex | 17618db21e1cf |
411324104434127 has 2 divisors, whose sum is σ = 411324104434128. Its totient is φ = 411324104434126.
The previous prime is 411324104434091. The next prime is 411324104434157. The reversal of 411324104434127 is 721434401423114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 411324104434127 - 222 = 411324100239823 is a prime.
It is a super-2 number, since 2×4113241044341272 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411324104434157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205662052217063 + 205662052217064.
It is an arithmetic number, because the mean of its divisors is an integer number (205662052217064).
Almost surely, 2411324104434127 is an apocalyptic number.
411324104434127 is a deficient number, since it is larger than the sum of its proper divisors (1).
411324104434127 is an equidigital number, since it uses as much as digits as its factorization.
411324104434127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 258048, while the sum is 41.
The spelling of 411324104434127 in words is "four hundred eleven trillion, three hundred twenty-four billion, one hundred four million, four hundred thirty-four thousand, one hundred twenty-seven".
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