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411324104434157 is a prime number
BaseRepresentation
bin101110110000110001101101…
…1001000011110000111101101
31222221101012102001120221121222
41131201203123020132013231
5412403113231213343112
64014451403541233125
7152432120516302505
oct13541433310360755
91887335361527558
10411324104434157
1110a073633834a72
123a17144a4027a5
13148689096038a5
14738029b384a05
15328473d216372
hex17618db21e1ed

411324104434157 has 2 divisors, whose sum is σ = 411324104434158. Its totient is φ = 411324104434156.

The previous prime is 411324104434127. The next prime is 411324104434231. The reversal of 411324104434157 is 751434401423114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 321122851849801 + 90201252584356 = 17919901^2 + 9497434^2 .

It is a cyclic number.

It is not a de Polignac number, because 411324104434157 - 222 = 411324100239853 is a prime.

It is a super-2 number, since 2×4113241044341572 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411324104434127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205662052217078 + 205662052217079.

It is an arithmetic number, because the mean of its divisors is an integer number (205662052217079).

Almost surely, 2411324104434157 is an apocalyptic number.

It is an amenable number.

411324104434157 is a deficient number, since it is larger than the sum of its proper divisors (1).

411324104434157 is an equidigital number, since it uses as much as digits as its factorization.

411324104434157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 645120, while the sum is 44.

The spelling of 411324104434157 in words is "four hundred eleven trillion, three hundred twenty-four billion, one hundred four million, four hundred thirty-four thousand, one hundred fifty-seven".