Base | Representation |
---|---|
bin | 10010101101001000101000… |
… | …10010101011010011111111 |
3 | 12101122022002101010020111012 |
4 | 21112210110102223103333 |
5 | 20342411340002442421 |
6 | 223252203422145435 |
7 | 11443531042101506 |
oct | 1126442422532377 |
9 | 171568071106435 |
10 | 41133242234111 |
11 | 12119567999615 |
12 | 4743a9372227b |
13 | 19c4b04373041 |
14 | a22c0684b83d |
15 | 4b4e83c8895b |
hex | 2569144ab4ff |
41133242234111 has 2 divisors, whose sum is σ = 41133242234112. Its totient is φ = 41133242234110.
The previous prime is 41133242234089. The next prime is 41133242234177. The reversal of 41133242234111 is 11143224233114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41133242234111 - 210 = 41133242233087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41133242234311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566621117055 + 20566621117056.
It is an arithmetic number, because the mean of its divisors is an integer number (20566621117056).
Almost surely, 241133242234111 is an apocalyptic number.
41133242234111 is a deficient number, since it is larger than the sum of its proper divisors (1).
41133242234111 is an equidigital number, since it uses as much as digits as its factorization.
41133242234111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13824, while the sum is 32.
Adding to 41133242234111 its reverse (11143224233114), we get a palindrome (52276466467225).
The spelling of 41133242234111 in words is "forty-one trillion, one hundred thirty-three billion, two hundred forty-two million, two hundred thirty-four thousand, one hundred eleven".
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