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41133242234177 is a prime number
BaseRepresentation
bin10010101101001000101000…
…10010101011010101000001
312101122022002101010020120122
421112210110102223111001
520342411340002443202
6223252203422150025
711443531042101632
oct1126442422532501
9171568071106518
1041133242234177
1112119567999675
124743a93722315
1319c4b04373092
14a22c0684b889
154b4e83c889a2
hex2569144ab541

41133242234177 has 2 divisors, whose sum is σ = 41133242234178. Its totient is φ = 41133242234176.

The previous prime is 41133242234111. The next prime is 41133242234179. The reversal of 41133242234177 is 77143224233114.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33689097501361 + 7444144732816 = 5804231^2 + 2728396^2 .

It is a cyclic number.

It is not a de Polignac number, because 41133242234177 - 212 = 41133242230081 is a prime.

Together with 41133242234179, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (41133242234179) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566621117088 + 20566621117089.

It is an arithmetic number, because the mean of its divisors is an integer number (20566621117089).

Almost surely, 241133242234177 is an apocalyptic number.

It is an amenable number.

41133242234177 is a deficient number, since it is larger than the sum of its proper divisors (1).

41133242234177 is an equidigital number, since it uses as much as digits as its factorization.

41133242234177 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 677376, while the sum is 44.

The spelling of 41133242234177 in words is "forty-one trillion, one hundred thirty-three billion, two hundred forty-two million, two hundred thirty-four thousand, one hundred seventy-seven".