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41133351414055 = 58226670282811
BaseRepresentation
bin10010101101001000110101…
…10011001010100100100111
312101122022100222120011012211
421112210122303022210213
520342412100430222210
6223252222322224251
711443533536106415
oct1126443263124447
9171568328504184
1041133351414055
111211961359007a
124743b041b5087
1319c4b20b7c064
14a22c1714c2b5
154b4e8d65338a
hex25691acca927

41133351414055 has 4 divisors (see below), whose sum is σ = 49360021696872. Its totient is φ = 32906681131240.

The previous prime is 41133351414011. The next prime is 41133351414091. The reversal of 41133351414055 is 55041415333114.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 41133351414055 - 237 = 40995912460583 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41133351413999 and 41133351414017.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4113335141401 + ... + 4113335141410.

It is an arithmetic number, because the mean of its divisors is an integer number (12340005424218).

Almost surely, 241133351414055 is an apocalyptic number.

41133351414055 is a deficient number, since it is larger than the sum of its proper divisors (8226670282817).

41133351414055 is an equidigital number, since it uses as much as digits as its factorization.

41133351414055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8226670282816.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 41133351414055 its reverse (55041415333114), we get a palindrome (96174766747169).

The spelling of 41133351414055 in words is "forty-one trillion, one hundred thirty-three billion, three hundred fifty-one million, four hundred fourteen thousand, fifty-five".

Divisors: 1 5 8226670282811 41133351414055