Base | Representation |
---|---|
bin | 10010101101001000110101… |
… | …10011001010100100100111 |
3 | 12101122022100222120011012211 |
4 | 21112210122303022210213 |
5 | 20342412100430222210 |
6 | 223252222322224251 |
7 | 11443533536106415 |
oct | 1126443263124447 |
9 | 171568328504184 |
10 | 41133351414055 |
11 | 1211961359007a |
12 | 4743b041b5087 |
13 | 19c4b20b7c064 |
14 | a22c1714c2b5 |
15 | 4b4e8d65338a |
hex | 25691acca927 |
41133351414055 has 4 divisors (see below), whose sum is σ = 49360021696872. Its totient is φ = 32906681131240.
The previous prime is 41133351414011. The next prime is 41133351414091. The reversal of 41133351414055 is 55041415333114.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 41133351414055 - 237 = 40995912460583 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 41133351413999 and 41133351414017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4113335141401 + ... + 4113335141410.
It is an arithmetic number, because the mean of its divisors is an integer number (12340005424218).
Almost surely, 241133351414055 is an apocalyptic number.
41133351414055 is a deficient number, since it is larger than the sum of its proper divisors (8226670282817).
41133351414055 is an equidigital number, since it uses as much as digits as its factorization.
41133351414055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8226670282816.
The product of its (nonzero) digits is 216000, while the sum is 40.
Adding to 41133351414055 its reverse (55041415333114), we get a palindrome (96174766747169).
The spelling of 41133351414055 in words is "forty-one trillion, one hundred thirty-three billion, three hundred fifty-one million, four hundred fourteen thousand, fifty-five".
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