Base | Representation |
---|---|
bin | 111011110110110110001… |
… | …100100010110101000101 |
3 | 112120020020202201210222101 |
4 | 323312312030202311011 |
5 | 1014343110123201343 |
6 | 12425350441032101 |
7 | 603115260613225 |
oct | 73666614426505 |
9 | 15506222653871 |
10 | 4113340443973 |
11 | 134650449a782 |
12 | 565239485631 |
13 | 23ab6a3985b7 |
14 | 10313002a085 |
15 | 71ee6493e4d |
hex | 3bdb6322d45 |
4113340443973 has 2 divisors, whose sum is σ = 4113340443974. Its totient is φ = 4113340443972.
The previous prime is 4113340443967. The next prime is 4113340444009. The reversal of 4113340443973 is 3793440433114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2926911915684 + 1186428528289 = 1710822^2 + 1089233^2 .
It is a cyclic number.
It is not a de Polignac number, because 4113340443973 - 237 = 3975901490501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4113340443923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056670221986 + 2056670221987.
It is an arithmetic number, because the mean of its divisors is an integer number (2056670221987).
Almost surely, 24113340443973 is an apocalyptic number.
It is an amenable number.
4113340443973 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113340443973 is an equidigital number, since it uses as much as digits as its factorization.
4113340443973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1306368, while the sum is 46.
The spelling of 4113340443973 in words is "four trillion, one hundred thirteen billion, three hundred forty million, four hundred forty-three thousand, nine hundred seventy-three".
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