4113403121 has 2 divisors, whose sum is σ = 4113403122. Its totient is φ = 4113403120.

The previous prime is 4113403103. The next prime is 4113403139. The reversal of 4113403121 is 1213043114.

4113403121 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (4113403103) and next prime (4113403139).

It can be written as a sum of positive squares in only one way, i.e., 3044832400 + 1068570721 = 55180^2 + 32689^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4113403121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4113403093 and 4113403102.

It is not a weakly prime, because it can be changed into another prime (4113403171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056701560 + 2056701561.

It is an arithmetic number, because the mean of its divisors is an integer number (2056701561).

Almost surely, 2^4113403121 is an apocalyptic number.

It is an amenable number.

4113403121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113403121 is an equidigital number, since it uses as much as digits as its factorization.

4113403121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 4113403121 is about 64135.8177697923. The cubic root of 4113403121 is about 1602.2628296228.

Adding to 4113403121 its reverse (1213043114), we get a palindrome (5326446235).

The spelling of 4113403121 in words is "four billion, one hundred thirteen million, four hundred three thousand, one hundred twenty-one".