Base | Representation |
---|---|
bin | 10010101101001010001111… |
… | …00111110011101001100111 |
3 | 12101122101022101120120111202 |
4 | 21112211013213303221213 |
5 | 20342420120433130203 |
6 | 223252425104153115 |
7 | 11443561300014260 |
oct | 1126450747635147 |
9 | 171571271516452 |
10 | 41134103411303 |
11 | 1211996a014801 |
12 | 474409400879b |
13 | 19c4c108c5946 |
14 | a22c88d7d967 |
15 | 4b4ed4697388 |
hex | 2569479f3a67 |
41134103411303 has 4 divisors (see below), whose sum is σ = 47010403898640. Its totient is φ = 35257802923968.
The previous prime is 41134103411293. The next prime is 41134103411309. The reversal of 41134103411303 is 30311430143114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41134103411303 - 226 = 41134036302439 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41134103411309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2938150243658 + ... + 2938150243671.
It is an arithmetic number, because the mean of its divisors is an integer number (11752600974660).
Almost surely, 241134103411303 is an apocalyptic number.
41134103411303 is a deficient number, since it is larger than the sum of its proper divisors (5876300487337).
41134103411303 is an equidigital number, since it uses as much as digits as its factorization.
41134103411303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5876300487336.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 41134103411303 its reverse (30311430143114), we get a palindrome (71445533554417).
The spelling of 41134103411303 in words is "forty-one trillion, one hundred thirty-four billion, one hundred three million, four hundred eleven thousand, three hundred three".
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