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41134241411 is a prime number
BaseRepresentation
bin100110010011110010…
…101011011010000011
310221011201022222012122
4212103302223122003
51133220331211121
630521413314455
72654226166034
oct462362533203
9127151288178
1041134241411
111649923043a
127b7b935a2b
133b57061923
141dc30a0a8b
15110b3835ab
hex993cab683

41134241411 has 2 divisors, whose sum is σ = 41134241412. Its totient is φ = 41134241410.

The previous prime is 41134241377. The next prime is 41134241413. The reversal of 41134241411 is 11414243114.

It is a happy number.

41134241411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41134241411 - 26 = 41134241347 is a prime.

Together with 41134241413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (41134241413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20567120705 + 20567120706.

It is an arithmetic number, because the mean of its divisors is an integer number (20567120706).

Almost surely, 241134241411 is an apocalyptic number.

41134241411 is a deficient number, since it is larger than the sum of its proper divisors (1).

41134241411 is an equidigital number, since it uses as much as digits as its factorization.

41134241411 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1536, while the sum is 26.

Adding to 41134241411 its reverse (11414243114), we get a palindrome (52548484525).

The spelling of 41134241411 in words is "forty-one billion, one hundred thirty-four million, two hundred forty-one thousand, four hundred eleven".