4114013233333 has 4 divisors (see below), whose sum is σ = 4114275639040. Its totient is φ = 4113750827628.

The previous prime is 4114013233321. The next prime is 4114013233373. The reversal of 4114013233333 is 3333323104114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4114013233333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4114013233295 and 4114013233304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4114013233303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131179335 + ... + 131210692.

It is an arithmetic number, because the mean of its divisors is an integer number (1028568909760).

Almost surely, 2^{4114013233333} is an apocalyptic number.

It is an amenable number.

4114013233333 is a deficient number, since it is larger than the sum of its proper divisors (262405707).

4114013233333 is a wasteful number, since it uses less digits than its factorization.

4114013233333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262405706.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 4114013233333 its reverse (3333323104114), we get a palindrome (7447336337447).

The spelling of 4114013233333 in words is "four trillion, one hundred fourteen billion, thirteen million, two hundred thirty-three thousand, three hundred thirty-three".