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4114013312201 = 13316462562477
BaseRepresentation
bin111011110111011110010…
…011010101010011001001
3112120021222122212001122212
4323313132103111103021
51014400444401442301
612425541314554505
7603141041113202
oct73673623252311
915507878761585
104114013312201
11134681a298621
125653a6898a35
1323ac468c8390
141031955405a9
15720355a74bb
hex3bdde4d54c9

4114013312201 has 4 divisors (see below), whose sum is σ = 4430475874692. Its totient is φ = 3797550749712.

The previous prime is 4114013312197. The next prime is 4114013312231. The reversal of 4114013312201 is 1022133104114.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 216452910025 + 3897560402176 = 465245^2 + 1974224^2 .

It is a cyclic number.

It is not a de Polignac number, because 4114013312201 - 22 = 4114013312197 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4114013312231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158231281226 + ... + 158231281251.

It is an arithmetic number, because the mean of its divisors is an integer number (1107618968673).

Almost surely, 24114013312201 is an apocalyptic number.

It is an amenable number.

4114013312201 is a deficient number, since it is larger than the sum of its proper divisors (316462562491).

4114013312201 is a wasteful number, since it uses less digits than its factorization.

4114013312201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 316462562490.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 4114013312201 its reverse (1022133104114), we get a palindrome (5136146416315).

The spelling of 4114013312201 in words is "four trillion, one hundred fourteen billion, thirteen million, three hundred twelve thousand, two hundred one".

Divisors: 1 13 316462562477 4114013312201