411403410443141 has 4 divisors (see below), whose sum is σ = 411458580547212. Its totient is φ = 411348240339072.

The previous prime is 411403410443101. The next prime is 411403410443147. The reversal of 411403410443141 is 141344014304114.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 154124056038241 + 257279354404900 = 12414671^2 + 16039930^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-411403410443141 is a prime.

It is a super-2 number, since 2×411403410443141² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411403410443147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27585040850 + ... + 27585055763.

It is an arithmetic number, because the mean of its divisors is an integer number (102864645136803).

Almost surely, 2^{411403410443141} is an apocalyptic number.

It is an amenable number.

411403410443141 is a deficient number, since it is larger than the sum of its proper divisors (55170104071).

411403410443141 is an equidigital number, since it uses as much as digits as its factorization.

411403410443141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55170104070.

The product of its (nonzero) digits is 36864, while the sum is 35.

Adding to 411403410443141 its reverse (141344014304114), we get a palindrome (552747424747255).

The spelling of 411403410443141 in words is "four hundred eleven trillion, four hundred three billion, four hundred ten million, four hundred forty-three thousand, one hundred forty-one".