Base | Representation |
---|---|
bin | 11000100001011… |
… | …001111010000101 |
3 | 1001200010210111101 |
4 | 120201121322011 |
5 | 1320310110203 |
6 | 104453540101 |
7 | 13123633135 |
oct | 3041317205 |
9 | 1050123441 |
10 | 411410053 |
11 | 1a125950a |
12 | b5944631 |
13 | 67307c02 |
14 | 3c8d4ac5 |
15 | 261b941d |
hex | 18859e85 |
411410053 has 2 divisors, whose sum is σ = 411410054. Its totient is φ = 411410052.
The previous prime is 411409991. The next prime is 411410063. The reversal of 411410053 is 350014114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 366224769 + 45185284 = 19137^2 + 6722^2 .
It is a cyclic number.
It is not a de Polignac number, because 411410053 - 221 = 409312901 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 411410053.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411410063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205705026 + 205705027.
It is an arithmetic number, because the mean of its divisors is an integer number (205705027).
Almost surely, 2411410053 is an apocalyptic number.
It is an amenable number.
411410053 is a deficient number, since it is larger than the sum of its proper divisors (1).
411410053 is an equidigital number, since it uses as much as digits as its factorization.
411410053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 19.
The square root of 411410053 is about 20283.2456229273. The cubic root of 411410053 is about 743.7465540598.
Adding to 411410053 its reverse (350014114), we get a palindrome (761424167).
The spelling of 411410053 in words is "four hundred eleven million, four hundred ten thousand, fifty-three".
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