4114132000011 has 12 divisors (see below), whose sum is σ = 6482874666840. Its totient is φ = 2493413333280.

The previous prime is 4114131999997. The next prime is 4114132000061. The reversal of 4114132000011 is 1100002314114.

4114132000011 is a `hidden beast` number, since 41 + 1 + 413 + 200 + 0 + 0 + 11 = 666.

It is not a de Polignac number, because 4114132000011 - 2¹³ = 4114131991819 is a prime.

It is a super-2 number, since 2×4114132000011² (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4114132000061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 20778444346 + ... + 20778444543.

It is an arithmetic number, because the mean of its divisors is an integer number (540239555570).

Almost surely, 2^{4114132000011} is an apocalyptic number.

4114132000011 is a deficient number, since it is larger than the sum of its proper divisors (2368742666829).

4114132000011 is a wasteful number, since it uses less digits than its factorization.

4114132000011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41556888906 (or 41556888903 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 4114132000011 its reverse (1100002314114), we get a palindrome (5214134314125).

The spelling of 4114132000011 in words is "four trillion, one hundred fourteen billion, one hundred thirty-two million, eleven", and thus it is an aban number.