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4114132000143 = 311124670666671
BaseRepresentation
bin111011110111100101011…
…000000101110110001111
3112120022021221012000220120
4323313211120011312033
51014401220243001033
612430001154520023
7603144012001164
oct73674530056617
915508257160816
104114132000143
111346880293630
1256541a596013
1323ac65383029
141031a71d806b
1572040bee1b3
hex3bde5605d8f

4114132000143 has 8 divisors (see below), whose sum is σ = 5984192000256. Its totient is φ = 2493413333400.

The previous prime is 4114132000127. The next prime is 4114132000177. The reversal of 4114132000143 is 3410002314114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 4114132000143 - 24 = 4114132000127 is a prime.

It is a super-2 number, since 2×41141320001432 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4114132000543) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62335333303 + ... + 62335333368.

It is an arithmetic number, because the mean of its divisors is an integer number (748024000032).

Almost surely, 24114132000143 is an apocalyptic number.

4114132000143 is a deficient number, since it is larger than the sum of its proper divisors (1870060000113).

4114132000143 is a wasteful number, since it uses less digits than its factorization.

4114132000143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124670666685.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 4114132000143 its reverse (3410002314114), we get a palindrome (7524134314257).

The spelling of 4114132000143 in words is "four trillion, one hundred fourteen billion, one hundred thirty-two million, one hundred forty-three", and thus it is an aban number.

Divisors: 1 3 11 33 124670666671 374012000013 1371377333381 4114132000143