Base | Representation |
---|---|
bin | 1111010100111000… |
… | …1011100100001011 |
3 | 101121201110201122202 |
4 | 3311032023210023 |
5 | 31411204312212 |
6 | 1520124110415 |
7 | 203644400402 |
oct | 36516134413 |
9 | 11551421582 |
10 | 4114135307 |
11 | 182135a827 |
12 | 96999540b |
13 | 5074740b9 |
14 | 2b0584639 |
15 | 1912bd0c2 |
hex | f538b90b |
4114135307 has 2 divisors, whose sum is σ = 4114135308. Its totient is φ = 4114135306.
The previous prime is 4114135253. The next prime is 4114135309. The reversal of 4114135307 is 7035314114.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4114135307 is a prime.
It is a super-2 number, since 2×41141353072 = 33852218648607968498, which contains 22 as substring.
Together with 4114135309, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4114135307.
It is not a weakly prime, because it can be changed into another prime (4114135309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057067653 + 2057067654.
It is an arithmetic number, because the mean of its divisors is an integer number (2057067654).
Almost surely, 24114135307 is an apocalyptic number.
4114135307 is a deficient number, since it is larger than the sum of its proper divisors (1).
4114135307 is an equidigital number, since it uses as much as digits as its factorization.
4114135307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 29.
The square root of 4114135307 is about 64141.5256054921. The cubic root of 4114135307 is about 1602.3578916090.
The spelling of 4114135307 in words is "four billion, one hundred fourteen million, one hundred thirty-five thousand, three hundred seven".
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