4114231121133 has 24 divisors (see below), whose sum is σ = 6795988969536. Its totient is φ = 2349520704000.

The previous prime is 4114231121107. The next prime is 4114231121141. The reversal of 4114231121133 is 3311211324114.

4114231121133 is a `hidden beast` number, since 4 + 11 + 423 + 11 + 211 + 3 + 3 = 666.

4114231121133 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 4114231121133 - 2³² = 4109936153837 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4114231121097 and 4114231121106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4114231121173) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20294283 + ... + 20496008.

It is an arithmetic number, because the mean of its divisors is an integer number (283166207064).

Almost surely, 2^{4114231121133} is an apocalyptic number.

It is an amenable number.

4114231121133 is a deficient number, since it is larger than the sum of its proper divisors (2681757848403).

4114231121133 is a wasteful number, since it uses less digits than its factorization.

4114231121133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40791905 (or 40791902 counting only the distinct ones).

The product of its digits is 1728, while the sum is 27.

Adding to 4114231121133 its reverse (3311211324114), we get a palindrome (7425442445247).

It can be divided in two parts, 4114231 and 121133, that added together give a square (4235364 = 2058²).

The spelling of 4114231121133 in words is "four trillion, one hundred fourteen billion, two hundred thirty-one million, one hundred twenty-one thousand, one hundred thirty-three".