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411423134101 = 758774733443
BaseRepresentation
bin1011111110010101011…
…10101101000110010101
31110022221210012201002121
411333022232231012111
523220043310242401
6513001041335541
741503306636660
oct5771256550625
91408853181077
10411423134101
111495356a70a1
12678a09375b1
132ca491170a5
1415cad33a6d7
15aa7e6baca1
hex5fcabad195

411423134101 has 4 divisors (see below), whose sum is σ = 470197867552. Its totient is φ = 352648400652.

The previous prime is 411423134071. The next prime is 411423134107. The reversal of 411423134101 is 101431324114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411423134101 - 217 = 411423003029 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411423134107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29387366715 + ... + 29387366728.

It is an arithmetic number, because the mean of its divisors is an integer number (117549466888).

Almost surely, 2411423134101 is an apocalyptic number.

It is an amenable number.

411423134101 is a deficient number, since it is larger than the sum of its proper divisors (58774733451).

411423134101 is an equidigital number, since it uses as much as digits as its factorization.

411423134101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58774733450.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 411423134101 its reverse (101431324114), we get a palindrome (512854458215).

The spelling of 411423134101 in words is "four hundred eleven billion, four hundred twenty-three million, one hundred thirty-four thousand, one hundred one".

Divisors: 1 7 58774733443 411423134101