Base | Representation |
---|---|
bin | 10010101101011001101100… |
… | …11001111101110111011111 |
3 | 12101200011201220112211101111 |
4 | 21112230312121331313133 |
5 | 20343034121023130210 |
6 | 223300320521322451 |
7 | 11444304065110630 |
oct | 1126546631756737 |
9 | 171604656484344 |
10 | 41142404505055 |
11 | 12122439843367 |
12 | 4745810036427 |
13 | 19c593462a639 |
14 | a23435623887 |
15 | 4b531d31a88a |
hex | 256b3667dddf |
41142404505055 has 16 divisors (see below), whose sum is σ = 57948838470720. Its totient is φ = 27449449800192.
The previous prime is 41142404505049. The next prime is 41142404505071. The reversal of 41142404505055 is 55050540424114.
It is not a de Polignac number, because 41142404505055 - 23 = 41142404505047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41142404504999 and 41142404505017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15885096970 + ... + 15885099559.
It is an arithmetic number, because the mean of its divisors is an integer number (3621802404420).
Almost surely, 241142404505055 is an apocalyptic number.
41142404505055 is a deficient number, since it is larger than the sum of its proper divisors (16806433965665).
41142404505055 is a wasteful number, since it uses less digits than its factorization.
41142404505055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31770196578.
The product of its (nonzero) digits is 320000, while the sum is 40.
Adding to 41142404505055 its reverse (55050540424114), we get a palindrome (96192944929169).
The spelling of 41142404505055 in words is "forty-one trillion, one hundred forty-two billion, four hundred four million, five hundred five thousand, fifty-five".
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