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4114244313103 = 171971228499347
BaseRepresentation
bin111011110111101100000…
…100100010000000001111
3112120022120202112010022211
4323313230010202000033
51014401433021004403
612430020250051251
7603146544435211
oct73675404420017
915508522463284
104114244313103
111346928724a61
12565450119b27
1323ac827180c2
141031b80b25b1
157204a9d706d
hex3bdec12200f

4114244313103 has 8 divisors (see below), whose sum is σ = 4378371676272. Its totient is φ = 3852573949056.

The previous prime is 4114244313089. The next prime is 4114244313143. The reversal of 4114244313103 is 3013134424114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4114244313103 - 217 = 4114244182031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4114244313143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 614246325 + ... + 614253022.

It is an arithmetic number, because the mean of its divisors is an integer number (547296459534).

Almost surely, 24114244313103 is an apocalyptic number.

4114244313103 is a deficient number, since it is larger than the sum of its proper divisors (264127363169).

4114244313103 is a wasteful number, since it uses less digits than its factorization.

4114244313103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1228499561.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 4114244313103 its reverse (3013134424114), we get a palindrome (7127378737217).

The spelling of 4114244313103 in words is "four trillion, one hundred fourteen billion, two hundred forty-four million, three hundred thirteen thousand, one hundred three".

Divisors: 1 17 197 3349 1228499347 20884488899 242014371359 4114244313103