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4114313010403 = 4918379456233
BaseRepresentation
bin111011110111110000001…
…010100101110011100011
3112120022202112210022022021
4323313300022211303203
51014402103112313103
612430031142322311
7603151340364661
oct73676012456343
915508675708267
104114313010403
111346963486292
1256546b129397
1323ac93a1b9ab
141031c3275c31
1572051a56bbd
hex3bdf02a5ce3

4114313010403 has 4 divisors (see below), whose sum is σ = 4122692467128. Its totient is φ = 4105933553680.

The previous prime is 4114313010371. The next prime is 4114313010407. The reversal of 4114313010403 is 3040103134114.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4114313010403 - 25 = 4114313010371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4114313010407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4189727626 + ... + 4189728607.

It is an arithmetic number, because the mean of its divisors is an integer number (1030673116782).

Almost surely, 24114313010403 is an apocalyptic number.

4114313010403 is a deficient number, since it is larger than the sum of its proper divisors (8379456725).

4114313010403 is an equidigital number, since it uses as much as digits as its factorization.

4114313010403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8379456724.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4114313010403 its reverse (3040103134114), we get a palindrome (7154416144517).

The spelling of 4114313010403 in words is "four trillion, one hundred fourteen billion, three hundred thirteen million, ten thousand, four hundred three".

Divisors: 1 491 8379456233 4114313010403