Base | Representation |
---|---|
bin | 111011110111110001010… |
… | …011011011100110111111 |
3 | 112120022210212201102101011 |
4 | 323313301103123212333 |
5 | 1014402123004331101 |
6 | 12430033103500051 |
7 | 603151661603542 |
oct | 73676123334677 |
9 | 15508725642334 |
10 | 4114332105151 |
11 | 1346973238474 |
12 | 5654755b7627 |
13 | 23ac97976068 |
14 | 1031c5a06859 |
15 | 72053579751 |
hex | 3bdf14db9bf |
4114332105151 has 2 divisors, whose sum is σ = 4114332105152. Its totient is φ = 4114332105150.
The previous prime is 4114332105113. The next prime is 4114332105229. The reversal of 4114332105151 is 1515012334114.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4114332105151 - 221 = 4114330007999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4114332105101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057166052575 + 2057166052576.
It is an arithmetic number, because the mean of its divisors is an integer number (2057166052576).
Almost surely, 24114332105151 is an apocalyptic number.
4114332105151 is a deficient number, since it is larger than the sum of its proper divisors (1).
4114332105151 is an equidigital number, since it uses as much as digits as its factorization.
4114332105151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 4114332105151 its reverse (1515012334114), we get a palindrome (5629344439265).
The spelling of 4114332105151 in words is "four trillion, one hundred fourteen billion, three hundred thirty-two million, one hundred five thousand, one hundred fifty-one".
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