Base | Representation |
---|---|
bin | 101110110001100100100101… |
… | …0011001010110011001010101 |
3 | 1222221202122101020120112122020 |
4 | 1131203021022121112121111 |
5 | 412411410442344443331 |
6 | 4015013511452323353 |
7 | 152443035562403022 |
oct | 13543111231263125 |
9 | 1887678336515566 |
10 | 411433345312341 |
11 | 10a1059a1424680 |
12 | 3a18a656a73559 |
13 | 14875cc8761091 |
14 | 73856a1800549 |
15 | 32874d385dc96 |
hex | 176324a656655 |
411433345312341 has 64 divisors (see below), whose sum is σ = 602572612561920. Its totient is φ = 247640569344000.
The previous prime is 411433345312333. The next prime is 411433345312369. The reversal of 411433345312341 is 143213543334114.
It is not a de Polignac number, because 411433345312341 - 23 = 411433345312333 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 411433345312293 and 411433345312302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (411433345311341) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 10945559575 + ... + 10945597163.
It is an arithmetic number, because the mean of its divisors is an integer number (9415197071280).
Almost surely, 2411433345312341 is an apocalyptic number.
It is an amenable number.
411433345312341 is a deficient number, since it is larger than the sum of its proper divisors (191139267249579).
411433345312341 is a wasteful number, since it uses less digits than its factorization.
411433345312341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41138.
The product of its digits is 622080, while the sum is 42.
Adding to 411433345312341 its reverse (143213543334114), we get a palindrome (554646888646455).
The spelling of 411433345312341 in words is "four hundred eleven trillion, four hundred thirty-three billion, three hundred forty-five million, three hundred twelve thousand, three hundred forty-one".
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