4115130032551 has 4 divisors (see below), whose sum is σ = 4357196505072. Its totient is φ = 3873063560032.

The previous prime is 4115130032521. The next prime is 4115130032557. The reversal of 4115130032551 is 1552300315114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4115130032551 - 2¹¹ = 4115130030503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4115130032557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121033236235 + ... + 121033236268.

It is an arithmetic number, because the mean of its divisors is an integer number (1089299126268).

Almost surely, 2^{4115130032551} is an apocalyptic number.

4115130032551 is a deficient number, since it is larger than the sum of its proper divisors (242066472521).

4115130032551 is a wasteful number, since it uses less digits than its factorization.

4115130032551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 242066472520.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 4115130032551 its reverse (1552300315114), we get a palindrome (5667430347665).

The spelling of 4115130032551 in words is "four trillion, one hundred fifteen billion, one hundred thirty million, thirty-two thousand, five hundred fifty-one".