Base | Representation |
---|---|
bin | 111011111000100010110… |
… | …110010100100110001111 |
3 | 112120101221210211021102220 |
4 | 323320202312110212033 |
5 | 1014410323303210210 |
6 | 12430251355550423 |
7 | 603211404130413 |
oct | 73704266244617 |
9 | 15511853737386 |
10 | 4115163335055 |
11 | 134725a469833 |
12 | 565667a5b413 |
13 | 23b09ac41986 |
14 | 103264180d43 |
15 | 720a151ec70 |
hex | 3be22d9498f |
4115163335055 has 16 divisors (see below), whose sum is σ = 6587336708064. Its totient is φ = 2193728654720.
The previous prime is 4115163335011. The next prime is 4115163335071. The reversal of 4115163335055 is 5505333615114.
It is not a de Polignac number, because 4115163335055 - 26 = 4115163334991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4115163334998 and 4115163335016.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 64037064 + ... + 64101293.
It is an arithmetic number, because the mean of its divisors is an integer number (411708544254).
Almost surely, 24115163335055 is an apocalyptic number.
4115163335055 is a deficient number, since it is larger than the sum of its proper divisors (2472173373009).
4115163335055 is a wasteful number, since it uses less digits than its factorization.
4115163335055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 128140506.
The product of its (nonzero) digits is 405000, while the sum is 42.
The spelling of 4115163335055 in words is "four trillion, one hundred fifteen billion, one hundred sixty-three million, three hundred thirty-five thousand, fifty-five".
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