Base | Representation |
---|---|
bin | 100110010101001000… |
… | …110110100111010101 |
3 | 10221020021211200021001 |
4 | 212111020312213111 |
5 | 1133242122103301 |
6 | 30523541423301 |
7 | 2654622203656 |
oct | 462510664725 |
9 | 127207750231 |
10 | 41156831701 |
11 | 164aaa5a8a7 |
12 | 7b8740ab31 |
13 | 3b5b94106b |
14 | 1dc60a152d |
15 | 110d346c01 |
hex | 9952369d5 |
41156831701 has 2 divisors, whose sum is σ = 41156831702. Its totient is φ = 41156831700.
The previous prime is 41156831663. The next prime is 41156831713. The reversal of 41156831701 is 10713865114.
It is a happy number.
41156831701 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26577476676 + 14579355025 = 163026^2 + 120745^2 .
It is a cyclic number.
It is not a de Polignac number, because 41156831701 - 211 = 41156829653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41156831731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20578415850 + 20578415851.
It is an arithmetic number, because the mean of its divisors is an integer number (20578415851).
Almost surely, 241156831701 is an apocalyptic number.
It is an amenable number.
41156831701 is a deficient number, since it is larger than the sum of its proper divisors (1).
41156831701 is an equidigital number, since it uses as much as digits as its factorization.
41156831701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 37.
The spelling of 41156831701 in words is "forty-one billion, one hundred fifty-six million, eight hundred thirty-one thousand, seven hundred one".
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