41200003113 has 4 divisors (see below), whose sum is σ = 54933337488. Its totient is φ = 27466668740.

The previous prime is 41200003099. The next prime is 41200003151. The reversal of 41200003113 is 31130000214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41200003113 - 2⁹ = 41200002601 is a prime.

It is a super-3 number, since 3×41200003113³ (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 41200003092 and 41200003101.

It is not an unprimeable number, because it can be changed into a prime (41200001113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6866667183 + ... + 6866667188.

It is an arithmetic number, because the mean of its divisors is an integer number (13733334372).

Almost surely, 2^41200003113 is an apocalyptic number.

It is an amenable number.

41200003113 is a deficient number, since it is larger than the sum of its proper divisors (13733334375).

41200003113 is a wasteful number, since it uses less digits than its factorization.

41200003113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13733334374.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 41200003113 its reverse (31130000214), we get a palindrome (72330003327).

The spelling of 41200003113 in words is "forty-one billion, two hundred million, three thousand, one hundred thirteen".