Base | Representation |
---|---|
bin | 11000100011101… |
… | …100111001011001 |
3 | 1001201021101101012 |
4 | 120203230321121 |
5 | 1320433341441 |
6 | 104514503305 |
7 | 13132021343 |
oct | 3043547131 |
9 | 1051241335 |
10 | 412012121 |
11 | 1a162a894 |
12 | b5b94b35 |
13 | 67488c71 |
14 | 3ca10293 |
15 | 262879eb |
hex | 188ece59 |
412012121 has 2 divisors, whose sum is σ = 412012122. Its totient is φ = 412012120.
The previous prime is 412012099. The next prime is 412012123. The reversal of 412012121 is 121210214.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 392475721 + 19536400 = 19811^2 + 4420^2 .
It is a cyclic number.
It is not a de Polignac number, because 412012121 - 218 = 411749977 is a prime.
Together with 412012123, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 412012096 and 412012105.
It is not a weakly prime, because it can be changed into another prime (412012123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206006060 + 206006061.
It is an arithmetic number, because the mean of its divisors is an integer number (206006061).
Almost surely, 2412012121 is an apocalyptic number.
It is an amenable number.
412012121 is a deficient number, since it is larger than the sum of its proper divisors (1).
412012121 is an equidigital number, since it uses as much as digits as its factorization.
412012121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 14.
The square root of 412012121 is about 20298.0817073929. The cubic root of 412012121 is about 744.1091831372.
Adding to 412012121 its reverse (121210214), we get a palindrome (533222335).
The spelling of 412012121 in words is "four hundred twelve million, twelve thousand, one hundred twenty-one".
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