Base | Representation |
---|---|
bin | 1011111111100110001… |
… | …10011011010101000011 |
3 | 1110101200222200111001112 |
4 | 11333303012123111003 |
5 | 23222440203111121 |
6 | 513152154353535 |
7 | 41526142645601 |
oct | 5776306332503 |
9 | 1411628614045 |
10 | 412100441411 |
11 | 149852a570aa |
12 | 67a4b72b8ab |
13 | 2cb2653c549 |
14 | 15d35288871 |
15 | aabdda975b |
hex | 5ff319b543 |
412100441411 has 2 divisors, whose sum is σ = 412100441412. Its totient is φ = 412100441410.
The previous prime is 412100441353. The next prime is 412100441413. The reversal of 412100441411 is 114144001214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 412100441411 - 210 = 412100440387 is a prime.
It is a super-2 number, since 2×4121004414112 (a number of 24 digits) contains 22 as substring.
Together with 412100441413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (412100441413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206050220705 + 206050220706.
It is an arithmetic number, because the mean of its divisors is an integer number (206050220706).
Almost surely, 2412100441411 is an apocalyptic number.
412100441411 is a deficient number, since it is larger than the sum of its proper divisors (1).
412100441411 is an equidigital number, since it uses as much as digits as its factorization.
412100441411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 412100441411 its reverse (114144001214), we get a palindrome (526244442625).
The spelling of 412100441411 in words is "four hundred twelve billion, one hundred million, four hundred forty-one thousand, four hundred eleven".
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