Base | Representation |
---|---|
bin | 111011111110000111001… |
… | …001011101001110110111 |
3 | 112120222101101221011010101 |
4 | 323332013021131032313 |
5 | 1020010044101240210 |
6 | 12433120454534531 |
7 | 603512500600654 |
oct | 73760711351667 |
9 | 15528341834111 |
10 | 4121141040055 |
11 | 1349847751aa6 |
12 | 566855967447 |
13 | 23b811502820 |
14 | 103670028c2b |
15 | 72301201a3a |
hex | 3bf8725d3b7 |
4121141040055 has 16 divisors (see below), whose sum is σ = 5374642664160. Its totient is φ = 3015383925888.
The previous prime is 4121141040017. The next prime is 4121141040059. The reversal of 4121141040055 is 5500401411214.
It is a cyclic number.
It is not a de Polignac number, because 4121141040055 - 215 = 4121141007287 is a prime.
It is a super-2 number, since 2×41211410400552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4121141040059) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 290828557 + ... + 290842726.
It is an arithmetic number, because the mean of its divisors is an integer number (335915166510).
Almost surely, 24121141040055 is an apocalyptic number.
4121141040055 is a deficient number, since it is larger than the sum of its proper divisors (1253501624105).
4121141040055 is a wasteful number, since it uses less digits than its factorization.
4121141040055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 581671410.
The product of its (nonzero) digits is 3200, while the sum is 28.
Adding to 4121141040055 its reverse (5500401411214), we get a palindrome (9621542451269).
The spelling of 4121141040055 in words is "four trillion, one hundred twenty-one billion, one hundred forty-one million, forty thousand, fifty-five".
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