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4121141040055 = 513109581671283
BaseRepresentation
bin111011111110000111001…
…001011101001110110111
3112120222101101221011010101
4323332013021131032313
51020010044101240210
612433120454534531
7603512500600654
oct73760711351667
915528341834111
104121141040055
111349847751aa6
12566855967447
1323b811502820
14103670028c2b
1572301201a3a
hex3bf8725d3b7

4121141040055 has 16 divisors (see below), whose sum is σ = 5374642664160. Its totient is φ = 3015383925888.

The previous prime is 4121141040017. The next prime is 4121141040059. The reversal of 4121141040055 is 5500401411214.

It is a cyclic number.

It is not a de Polignac number, because 4121141040055 - 215 = 4121141007287 is a prime.

It is a super-2 number, since 2×41211410400552 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4121141040059) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 290828557 + ... + 290842726.

It is an arithmetic number, because the mean of its divisors is an integer number (335915166510).

Almost surely, 24121141040055 is an apocalyptic number.

4121141040055 is a deficient number, since it is larger than the sum of its proper divisors (1253501624105).

4121141040055 is a wasteful number, since it uses less digits than its factorization.

4121141040055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 581671410.

The product of its (nonzero) digits is 3200, while the sum is 28.

Adding to 4121141040055 its reverse (5500401411214), we get a palindrome (9621542451269).

The spelling of 4121141040055 in words is "four trillion, one hundred twenty-one billion, one hundred forty-one million, forty thousand, fifty-five".

Divisors: 1 5 13 65 109 545 1417 7085 581671283 2908356415 7561726679 37808633395 63402169847 317010849235 824228208011 4121141040055