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41221411312999 is a prime number
BaseRepresentation
bin10010101111101100110111…
…00101000001010101100111
312101221201200000210112000111
421113312123211001111213
520400332422244003444
6223400504355353451
711453101666644601
oct1127663345012547
9171851600715014
1041221411312999
11121529a2056565
124758b9b2b2887
131a00215a69c38
14a271ac504171
154b73e4500234
hex257d9b941567

41221411312999 has 2 divisors, whose sum is σ = 41221411313000. Its totient is φ = 41221411312998.

The previous prime is 41221411312993. The next prime is 41221411313083. The reversal of 41221411312999 is 99921311412214.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 41221411312999 - 27 = 41221411312871 is a prime.

It is a super-2 number, since 2×412214113129992 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41221411312993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20610705656499 + 20610705656500.

It is an arithmetic number, because the mean of its divisors is an integer number (20610705656500).

Almost surely, 241221411312999 is an apocalyptic number.

41221411312999 is a deficient number, since it is larger than the sum of its proper divisors (1).

41221411312999 is an equidigital number, since it uses as much as digits as its factorization.

41221411312999 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 279936, while the sum is 49.

The spelling of 41221411312999 in words is "forty-one trillion, two hundred twenty-one billion, four hundred eleven million, three hundred twelve thousand, nine hundred ninety-nine".