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412302122431 is a prime number
BaseRepresentation
bin1011111111111110001…
…11110001110110111111
31110102020001011221101221
411333333013301312333
523223343320404211
6513224201214211
741534142134113
oct5777707616677
91412201157357
10412302122431
11149946888031
1267aa7191367
132cb59264a24
1415d53d87743
15aad1946c71
hex5fff1f1dbf

412302122431 has 2 divisors, whose sum is σ = 412302122432. Its totient is φ = 412302122430.

The previous prime is 412302122429. The next prime is 412302122447. The reversal of 412302122431 is 134221203214.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 412302122431 - 21 = 412302122429 is a prime.

It is a super-2 number, since 2×4123021224312 (a number of 24 digits) contains 22 as substring.

Together with 412302122429, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 412302122396 and 412302122405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412302122231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206151061215 + 206151061216.

It is an arithmetic number, because the mean of its divisors is an integer number (206151061216).

Almost surely, 2412302122431 is an apocalyptic number.

412302122431 is a deficient number, since it is larger than the sum of its proper divisors (1).

412302122431 is an equidigital number, since it uses as much as digits as its factorization.

412302122431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 412302122431 its reverse (134221203214), we get a palindrome (546523325645).

The spelling of 412302122431 in words is "four hundred twelve billion, three hundred two million, one hundred twenty-two thousand, four hundred thirty-one".