Base | Representation |
---|---|
bin | 10010101111111101110010… |
… | …11011011100110010111111 |
3 | 12101222121010120122001210111 |
4 | 21113332321123130302333 |
5 | 20401010032011230403 |
6 | 223405010421450451 |
7 | 11453543163662104 |
oct | 1127767133346277 |
9 | 171877116561714 |
10 | 41230502055103 |
11 | 12156837595669 |
12 | 475a8b7870a27 |
13 | 1a0103426bb8a |
14 | a277d19baaab |
15 | 4b777765356d |
hex | 257fb96dccbf |
41230502055103 has 2 divisors, whose sum is σ = 41230502055104. Its totient is φ = 41230502055102.
The previous prime is 41230502055101. The next prime is 41230502055131. The reversal of 41230502055103 is 30155020503214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41230502055103 - 21 = 41230502055101 is a prime.
Together with 41230502055101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41230502055101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20615251027551 + 20615251027552.
It is an arithmetic number, because the mean of its divisors is an integer number (20615251027552).
Almost surely, 241230502055103 is an apocalyptic number.
41230502055103 is a deficient number, since it is larger than the sum of its proper divisors (1).
41230502055103 is an equidigital number, since it uses as much as digits as its factorization.
41230502055103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 41230502055103 its reverse (30155020503214), we get a palindrome (71385522558317).
The spelling of 41230502055103 in words is "forty-one trillion, two hundred thirty billion, five hundred two million, fifty-five thousand, one hundred three".
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