4124120043149 has 2 divisors, whose sum is σ = 4124120043150. Its totient is φ = 4124120043148.

The previous prime is 4124120043137. The next prime is 4124120043151. The reversal of 4124120043149 is 9413400214214.

4124120043149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3985285557124 + 138834486025 = 1996318^2 + 372605^2 .

It is a cyclic number.

It is not a de Polignac number, because 4124120043149 - 2⁴ = 4124120043133 is a prime.

It is a super-2 number, since 2×4124120043149² (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 4124120043151, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4124120043349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062060021574 + 2062060021575.

It is an arithmetic number, because the mean of its divisors is an integer number (2062060021575).

Almost surely, 2^{4124120043149} is an apocalyptic number.

It is an amenable number.

4124120043149 is a deficient number, since it is larger than the sum of its proper divisors (1).

4124120043149 is an equidigital number, since it uses as much as digits as its factorization.

4124120043149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 35.

The spelling of 4124120043149 in words is "four trillion, one hundred twenty-four billion, one hundred twenty million, forty-three thousand, one hundred forty-nine".