Base | Representation |
---|---|
bin | 10010110000010010001001… |
… | …10111010011001010100101 |
3 | 12102000122100020222102020112 |
4 | 21120021010313103022211 |
5 | 20401144422404321201 |
6 | 223414015121542405 |
7 | 11454411054142556 |
oct | 1130110467231245 |
9 | 172018306872215 |
10 | 41241431323301 |
11 | 12160435902620 |
12 | 4760a47aa4a05 |
13 | 1a0208662c891 |
14 | a2814b31832d |
15 | 4b7bb6dc00bb |
hex | 258244dd32a5 |
41241431323301 has 16 divisors (see below), whose sum is σ = 46544302074816. Its totient is φ = 36215610000000.
The previous prime is 41241431323243. The next prime is 41241431323319. The reversal of 41241431323301 is 10332313414214.
It is a cyclic number.
It is not a de Polignac number, because 41241431323301 - 222 = 41241427128997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41241431323201) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 452649575 + ... + 452740676.
It is an arithmetic number, because the mean of its divisors is an integer number (2909018879676).
Almost surely, 241241431323301 is an apocalyptic number.
41241431323301 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
It is an amenable number.
41241431323301 is a deficient number, since it is larger than the sum of its proper divisors (5302870751515).
41241431323301 is a wasteful number, since it uses less digits than its factorization.
41241431323301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 905390404.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 41241431323301 its reverse (10332313414214), we get a palindrome (51573744737515).
The spelling of 41241431323301 in words is "forty-one trillion, two hundred forty-one billion, four hundred thirty-one million, three hundred twenty-three thousand, three hundred one".
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