Base | Representation |
---|---|
bin | 10010110000010101101001… |
… | …11010100000001011110111 |
3 | 12102000211012021022121201022 |
4 | 21120022310322200023313 |
5 | 20401212300132230010 |
6 | 223414525434251355 |
7 | 11454505462005506 |
oct | 1130126472401367 |
9 | 172024167277638 |
10 | 41243311211255 |
11 | 1216120aa7122a |
12 | 4761291586b5b |
13 | 1a022c5c4100a |
14 | a28288c6883d |
15 | 4b7c76e58d55 |
hex | 2582b4ea02f7 |
41243311211255 has 4 divisors (see below), whose sum is σ = 49491973453512. Its totient is φ = 32994648969000.
The previous prime is 41243311211251. The next prime is 41243311211257. The reversal of 41243311211255 is 55211211334214.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 41243311211255 - 22 = 41243311211251 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41243311211251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4124331121121 + ... + 4124331121130.
It is an arithmetic number, because the mean of its divisors is an integer number (12372993363378).
Almost surely, 241243311211255 is an apocalyptic number.
41243311211255 is a deficient number, since it is larger than the sum of its proper divisors (8248662242257).
41243311211255 is an equidigital number, since it uses as much as digits as its factorization.
41243311211255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8248662242256.
The product of its digits is 28800, while the sum is 35.
Adding to 41243311211255 its reverse (55211211334214), we get a palindrome (96454522545469).
The spelling of 41243311211255 in words is "forty-one trillion, two hundred forty-three billion, three hundred eleven million, two hundred eleven thousand, two hundred fifty-five".
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