Base | Representation |
---|---|
bin | 111100000001010111111… |
… | …100101011110100001111 |
3 | 112121022102112121120012202 |
4 | 330001113330223310033 |
5 | 1020034232344130223 |
6 | 12434500234152115 |
7 | 603665345430242 |
oct | 74012774536417 |
9 | 15538375546182 |
10 | 4124644130063 |
11 | 135028509a406 |
12 | 567472b8263b |
13 | 23bc4c1b1752 |
14 | 1038c338d259 |
15 | 72458a1e428 |
hex | 3c057f2bd0f |
4124644130063 has 12 divisors (see below), whose sum is σ = 4416938773968. Its totient is φ = 3849084639840.
The previous prime is 4124644130051. The next prime is 4124644130153. The reversal of 4124644130063 is 3600314464214.
It is not a de Polignac number, because 4124644130063 - 232 = 4120349162767 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4124644129999 and 4124644130026.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4124644130263) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 95064395 + ... + 95107772.
It is an arithmetic number, because the mean of its divisors is an integer number (368078231164).
Almost surely, 24124644130063 is an apocalyptic number.
4124644130063 is a deficient number, since it is larger than the sum of its proper divisors (292294643905).
4124644130063 is a wasteful number, since it uses less digits than its factorization.
4124644130063 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190172254 (or 190172231 counting only the distinct ones).
The product of its (nonzero) digits is 165888, while the sum is 38.
Adding to 4124644130063 its reverse (3600314464214), we get a palindrome (7724958594277).
The spelling of 4124644130063 in words is "four trillion, one hundred twenty-four billion, six hundred forty-four million, one hundred thirty thousand, sixty-three".
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