4125213043741 has 4 divisors (see below), whose sum is σ = 4146811017984. Its totient is φ = 4103615069500.

The previous prime is 4125213043733. The next prime is 4125213043781. The reversal of 4125213043741 is 1473403125214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4125213043741 - 2³ = 4125213043733 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4125213043741.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4125213043781) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10798986835 + ... + 10798987216.

It is an arithmetic number, because the mean of its divisors is an integer number (1036702754496).

Almost surely, 2^{4125213043741} is an apocalyptic number.

It is an amenable number.

4125213043741 is a deficient number, since it is larger than the sum of its proper divisors (21597974243).

4125213043741 is a wasteful number, since it uses less digits than its factorization.

4125213043741 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21597974242.

The product of its (nonzero) digits is 80640, while the sum is 37.

Adding to 4125213043741 its reverse (1473403125214), we get a palindrome (5598616168955).

The spelling of 4125213043741 in words is "four trillion, one hundred twenty-five billion, two hundred thirteen million, forty-three thousand, seven hundred forty-one".