Base | Representation |
---|---|
bin | 111100000110010111001… |
… | …011111000000100001101 |
3 | 112121211020210201012022202 |
4 | 330012113023320010031 |
5 | 1020131220002404201 |
6 | 12441143522051245 |
7 | 604245152103455 |
oct | 74062713700415 |
9 | 15554223635282 |
10 | 4130000044301 |
11 | 13525833a100a |
12 | 5685087a9b25 |
13 | 23c5c39b7481 |
14 | 103c7081ad65 |
15 | 7266dd2bc6b |
hex | 3c1972f810d |
4130000044301 has 2 divisors, whose sum is σ = 4130000044302. Its totient is φ = 4130000044300.
The previous prime is 4130000044279. The next prime is 4130000044399. The reversal of 4130000044301 is 1034400000314.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3529987138276 + 600012906025 = 1878826^2 + 774605^2 .
It is a cyclic number.
It is not a de Polignac number, because 4130000044301 - 218 = 4129999782157 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4130000844301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065000022150 + 2065000022151.
It is an arithmetic number, because the mean of its divisors is an integer number (2065000022151).
Almost surely, 24130000044301 is an apocalyptic number.
It is an amenable number.
4130000044301 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130000044301 is an equidigital number, since it uses as much as digits as its factorization.
4130000044301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 4130000044301 its reverse (1034400000314), we get a palindrome (5164400044615).
The spelling of 4130000044301 in words is "four trillion, one hundred thirty billion, forty-four thousand, three hundred one".
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