Base | Representation |
---|---|
bin | 111100000110010111110… |
… | …010101010011100011011 |
3 | 112121211021111211202221202 |
4 | 330012113302222130123 |
5 | 1020131230103241443 |
6 | 12441144524024415 |
7 | 604245334402325 |
oct | 74062762523433 |
9 | 15554244752852 |
10 | 4130010212123 |
11 | 1352589106274 |
12 | 56851009210b |
13 | 23c5c5b37533 |
14 | 103c71d06615 |
15 | 7266eb897b8 |
hex | 3c197caa71b |
4130010212123 has 2 divisors, whose sum is σ = 4130010212124. Its totient is φ = 4130010212122.
The previous prime is 4130010212093. The next prime is 4130010212129. The reversal of 4130010212123 is 3212120100314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4130010212123 - 210 = 4130010211099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4130010212095 and 4130010212104.
It is not a weakly prime, because it can be changed into another prime (4130010212129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065005106061 + 2065005106062.
It is an arithmetic number, because the mean of its divisors is an integer number (2065005106062).
Almost surely, 24130010212123 is an apocalyptic number.
4130010212123 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130010212123 is an equidigital number, since it uses as much as digits as its factorization.
4130010212123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 4130010212123 its reverse (3212120100314), we get a palindrome (7342130312437).
The spelling of 4130010212123 in words is "four trillion, one hundred thirty billion, ten million, two hundred twelve thousand, one hundred twenty-three".
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