Base | Representation |
---|---|
bin | 10010110001111111101011… |
… | …00110010011101110110101 |
3 | 12102020021010002222001101222 |
4 | 21120333311212103232311 |
5 | 20403130333114330003 |
6 | 223501021511200125 |
7 | 11461562140222334 |
oct | 1130776546235665 |
9 | 172207102861358 |
10 | 41300231011253 |
11 | 12183369790455 |
12 | 4770317976045 |
13 | 1a077974b6546 |
14 | a2ad285d9d1b |
15 | 4b94a9074c38 |
hex | 258ff5993bb5 |
41300231011253 has 2 divisors, whose sum is σ = 41300231011254. Its totient is φ = 41300231011252.
The previous prime is 41300231011147. The next prime is 41300231011261. The reversal of 41300231011253 is 35211013200314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36983219192689 + 4317011818564 = 6081383^2 + 2077742^2 .
It is a cyclic number.
It is not a de Polignac number, because 41300231011253 - 216 = 41300230945717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41300291011253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20650115505626 + 20650115505627.
It is an arithmetic number, because the mean of its divisors is an integer number (20650115505627).
Almost surely, 241300231011253 is an apocalyptic number.
It is an amenable number.
41300231011253 is a deficient number, since it is larger than the sum of its proper divisors (1).
41300231011253 is an equidigital number, since it uses as much as digits as its factorization.
41300231011253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 41300231011253 its reverse (35211013200314), we get a palindrome (76511244211567).
The spelling of 41300231011253 in words is "forty-one trillion, three hundred billion, two hundred thirty-one million, eleven thousand, two hundred fifty-three".
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