4130040404133 has 48 divisors (see below), whose sum is σ = 6922606387840. Its totient is φ = 2324025032832.

The previous prime is 4130040404123. The next prime is 4130040404159. The reversal of 4130040404133 is 3314040400314.

4130040404133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 4130040404133 - 2²¹ = 4130038306981 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4130040404097 and 4130040404106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4130040404123) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 725566 + ... + 2964207.

Almost surely, 2^{4130040404133} is an apocalyptic number.

It is an amenable number.

4130040404133 is a deficient number, since it is larger than the sum of its proper divisors (2792565983707).

4130040404133 is a wasteful number, since it uses less digits than its factorization.

4130040404133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3690058 (or 3690055 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 4130040404133 its reverse (3314040400314), we get a palindrome (7444080804447).

The spelling of 4130040404133 in words is "four trillion, one hundred thirty billion, forty million, four hundred four thousand, one hundred thirty-three".