Base | Representation |
---|---|
bin | 111100000110011101111… |
… | …111000010011101001101 |
3 | 112121211112202100211002011 |
4 | 330012131333002131031 |
5 | 1020131433203311001 |
6 | 12441203115101221 |
7 | 604251035530306 |
oct | 74063577023515 |
9 | 15554482324064 |
10 | 4130114119501 |
11 | 1352631826437 |
12 | 56853aa41811 |
13 | 23c6115186a6 |
14 | 103c81a337ad |
15 | 72678d61d51 |
hex | 3c19dfc274d |
4130114119501 has 2 divisors, whose sum is σ = 4130114119502. Its totient is φ = 4130114119500.
The previous prime is 4130114119493. The next prime is 4130114119513. The reversal of 4130114119501 is 1059114110314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3906927794025 + 223186325476 = 1976595^2 + 472426^2 .
It is a cyclic number.
It is not a de Polignac number, because 4130114119501 - 23 = 4130114119493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4130114116501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065057059750 + 2065057059751.
It is an arithmetic number, because the mean of its divisors is an integer number (2065057059751).
Almost surely, 24130114119501 is an apocalyptic number.
It is an amenable number.
4130114119501 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130114119501 is an equidigital number, since it uses as much as digits as its factorization.
4130114119501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 31.
Adding to 4130114119501 its reverse (1059114110314), we get a palindrome (5189228229815).
The spelling of 4130114119501 in words is "four trillion, one hundred thirty billion, one hundred fourteen million, one hundred nineteen thousand, five hundred one".
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