Base | Representation |
---|---|
bin | 1100000001010110100… |
… | …10100000001001111011 |
3 | 1110111010200112002001212 |
4 | 12000223102200021323 |
5 | 23231403020143003 |
6 | 513425511433335 |
7 | 41561410454006 |
oct | 6005322401173 |
9 | 1414120462055 |
10 | 413043131003 |
11 | 14a197096808 |
12 | 6807338584b |
13 | 2cc46931a39 |
14 | 15dc455853d |
15 | ab26a19dd8 |
hex | 602b4a027b |
413043131003 has 2 divisors, whose sum is σ = 413043131004. Its totient is φ = 413043131002.
The previous prime is 413043130979. The next prime is 413043131027. The reversal of 413043131003 is 300131340314.
It is a balanced prime because it is at equal distance from previous prime (413043130979) and next prime (413043131027).
It is a cyclic number.
It is not a de Polignac number, because 413043131003 - 214 = 413043114619 is a prime.
It is a super-2 number, since 2×4130431310032 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 413043131003.
It is not a weakly prime, because it can be changed into another prime (413043134003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206521565501 + 206521565502.
It is an arithmetic number, because the mean of its divisors is an integer number (206521565502).
Almost surely, 2413043131003 is an apocalyptic number.
413043131003 is a deficient number, since it is larger than the sum of its proper divisors (1).
413043131003 is an equidigital number, since it uses as much as digits as its factorization.
413043131003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 413043131003 its reverse (300131340314), we get a palindrome (713174471317).
The spelling of 413043131003 in words is "four hundred thirteen billion, forty-three million, one hundred thirty-one thousand, three".
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